for and if condition using JS

 

Unveiling the Mystery of Numbers: An Adventure in JavaScript

Introduction

Greetings, fellow coders! Today, we embark on a journey into the heart of JavaScript, where we'll unravel the mysteries of numbers. Our guide for this exploration is a small but powerful script that uses a for loop and if conditions to classify numbers as either even or odd. Let's dive right in!

The Code

Breaking Down the Script

In this code snippet, we have an array called numbers containing integers from 1 to 10. The script then employs a for loop to iterate through each number in the array.

The for Loop}

The loop initializes a variable i to 0, and as long as i is less than the length of the numbers array, it iterates, incrementing i with each cycle.

The if Condition

Inside the loop, there's an if condition that checks whether the current number (numbers[i]) is even or odd. If it's even, a message is logged indicating that the number is even; otherwise, it's identified as odd.

The Result

As the script runs, it diligently goes through each number in the array, unveiling their true identities as even or odd, and presents the findings on the console.

Conclusion

Our journey into the realm of JavaScript has been enlightening! We've witnessed how a combination of a for loop and if conditions can bring order to the world of numbers. Stay tuned for more coding adventures as we continue to explore the vast landscape of programming.