Unveiling the Mystery of Numbers: An Adventure in JavaScript Introduction Greetings, fellow coders! Today, we embark on a journey into the heart of JavaScript, where we'll unravel the mysteries of numbers. Our guide for this exploration is a small but powerful script that uses a for loop and if conditions to classify numbers as either even or odd. Let's dive right in! The Code Breaking Down the Script In this code snippet, we have an array called numbers containing integers from 1 to 10. The script then employs a for loop to iterate through each number in the array. The for Loop} The loop initializes a variable i to 0, and as long as i is less than the length of the numbers array, it iterates, incrementing i with each cycle. The if Condition Inside the loop, there's an if condition that checks whether the current number ( numbers[i] ) is even or odd. If it's even, a message is logged indicating that the number is even; otherwise, it's identified as odd....